14x^2-3x+2=9x^2-11x+6

Solution for 14x^2-3x+2=9x^2-11x+6 equation:

14x^2-3x+2=9x^2-11x+6

We move all terms to the left:

14x^2-3x+2-(9x^2-11x+6)=0

We get rid of parentheses

14x^2-9x^2-3x+11x-6+2=0

We add all the numbers together, and all the variables

5x^2+8x-4=0

a = 5; b = 8; c = -4;
Δ = b2-4ac
Δ = 82-4·5·(-4)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-12}{2*5}=\frac{-20}{10}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+12}{2*5}=\frac{4}{10}
=2/5
$